20x+x^2=156

Solution for 20x+x^2=156 equation:

20x+x^2=156

We move all terms to the left:

20x+x^2-(156)=0

a = 1; b = 20; c = -156;
Δ = b2-4ac
Δ = 202-4·1·(-156)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-32}{2*1}=\frac{-52}{2}
=-26
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+32}{2*1}=\frac{12}{2}
=6
$